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Section 4.3 Solving Systems with Matrix Inverses (MX3)

Subsection 4.3.1 Warm Up

Activity 4.3.1.

Which of the following matrices is invertible? Find the inverse for the one that is invertible.
  1. [1−10−110101]
  2. [1−13−11−110−2]

Subsection 4.3.2 Class Activities

Activity 4.3.2.

Consider the following linear system with a unique solution:
3x1−2x2−2x3−4x4=−72x1−x2−x3−x4=−1−x1+x3=−1−x2−2x4=−5
(a)
Suppose we let
T([x1x2x3x4])=[3x1−2x2−2x3−4x42x1−x2−x3−x4−x1+x3−x2−2x4].
Which of these choices would help us solve the given system?
  1. Compute T([−7−1−1−5])
  2. Find [x1x2x3x4] where T([x1x2x3x4])=[−7−1−1−5]
(b)
How can we express this in terms of matrix multiplication?
  1. [3−2−2−42−1−1−1−10100−10−2][x1x2x3x4]=[−7−1−1−5]
  2. [x1x2x3x4]=[3−2−2−42−1−1−1−10100−10−2][−7−1−1−5]
  3. [x1x2x3x4][3−2−2−42−1−1−1−10100−10−2]=[−7−1−1−5]
  4. [x1x2x3x4]=[−7−1−1−5][3−2−2−42−1−1−1−10100−10−2]
(c)
How could a matrix equation of the form Ax→=b→ be solved for x→?
  1. Multiply: (RREFA)(Ax→)=(RREFA)b→
  2. Add: (RREFA)+Ax→=(RREFA)+b→
  3. Multiply: (A−1)(Ax→)=(A−1)b→
  4. Add: (A−1)+Ax→=(A−1)+b→

Remark 4.3.3.

The linear system described by the augmented matrix [A∣b→] has exactly the same solution set as the matrix equation Ax→=b→.
When A is invertible, then we have both [A∣b→]∼[I∣x→] and x→=A−1b→, which can be seen as
Ax→=b→⇒A−1Ax→=A−1b→⇒x→=A−1b→

Subsection 4.3.3 Individual Practice

Activity 4.3.5.

Solving linear systems using matrix multiplication is most useful when we are working with one common coefficient matrix, and varying the right-hand side. That is, when we have Ax→=b→ for several different values of b→.
In the following, let A=[2−1−6213114] and consider the following questions about various equations of the form Ax→=b→?
(a)
Suppose that b→=[111]. If asked to solve the equation Ax→=b→, which of the following approaches do you prefer?
  1. Calculate RREF[A|b→].
  2. Calculate A−1 and then compute x→=A−1b→
(b)
Suppose that b→1,b→2,b→3=[111],[213],[−135]. If asked to solve each of the equations Ax→=b→1,Ax→=b→2,Ax→=b→3, which of the following approaches do you prefer?
  1. Calculate RREF[A|b→1], RREF[A|b→2], and RREF[A|b→3]
  2. Calculate A−1 and then compute x→=A−1b→1, x→=A−1b→2, and x→=A−1b→3
(c)
Suppose that b→1,…,b→10 are 10 distinct vectors. If asked to solve each of the equations Ax→=b→1,…,Ax→=b→10, which of the following approaches do you prefer?
  1. Calculate RREF[A|b→1], ... RREF[A|b→10].
  2. Calculate A−1 and then compute x→=A−1b→1, ... x→=A−1b→10.

Subsection 4.3.4 Videos

Video coming soon to this YouTube playlist
 1 
www.youtube.com/watch?v=kpOK7RhFEiQ&list=PLwXCBkIf7xBMo3zMnD7WVt39rANLlSdmj
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Exercises 4.3.5 Exercises

Subsection 4.3.6 Mathematical Writing Explorations

Exploration 4.3.6.

Use row reduction to find the inverse of the following general matrix. Give conditions on which this inverse exists.
[1bcdefghi]

Exploration 4.3.7.

Assume that H is invertible, and that HG is the zero matrix. Prove that G must be the zero matrix. Would this still be true if H were not invertible?

Exploration 4.3.8.

If H is invertible and r∈R, what is the inverse of rH?

Exploration 4.3.9.

If H and G are invertible, is H−1+G−1=(H+G)−1?

Exploration 4.3.10.

Prove that if A, P, and Q are invertible with PAQ=I, then A−1=QP.

Subsection 4.3.7 Sample Problem and Solution