🔗 Activity 4.3.1. 🔗 🔗Which of the following matrices is invertible? Find the inverse for the one that is invertible. [1−10−110101] [1−13−11−110−2]
🔗 Activity 4.3.2. 🔗 🔗Consider the following linear system with a unique solution: 3x1−2x2−2x3−4x4=−72x1−x2−x3−x4=−1−x1+x3=−1−x2−2x4=−5 🔗(a) 🔗 🔗Suppose we let .T([x1x2x3x4])=[3x1−2x2−2x3−4x42x1−x2−x3−x4−x1+x3−x2−2x4]. 🔗Which of these choices would help us solve the given system? Compute T([−7−1−1−5]) Find [x1x2x3x4] where T([x1x2x3x4])=[−7−1−1−5] 🔗(b) 🔗How can we express this in terms of matrix multiplication? [3−2−2−42−1−1−1−10100−10−2][x1x2x3x4]=[−7−1−1−5] [x1x2x3x4]=[3−2−2−42−1−1−1−10100−10−2][−7−1−1−5] [x1x2x3x4][3−2−2−42−1−1−1−10100−10−2]=[−7−1−1−5] [x1x2x3x4]=[−7−1−1−5][3−2−2−42−1−1−1−10100−10−2] 🔗(c) 🔗 🔗How could a matrix equation of the form Ax→=b→ be solved for ?x→? Multiply: (RREFA)(Ax→)=(RREFA)b→ Add: (RREFA)+Ax→=(RREFA)+b→ Multiply: (A−1)(Ax→)=(A−1)b→ Add: (A−1)+Ax→=(A−1)+b→ 🔗(d) 🔗Find [x1x2x3x4] using the method you chose in (c).
🔗(a) 🔗 🔗Suppose we let .T([x1x2x3x4])=[3x1−2x2−2x3−4x42x1−x2−x3−x4−x1+x3−x2−2x4]. 🔗Which of these choices would help us solve the given system? Compute T([−7−1−1−5]) Find [x1x2x3x4] where T([x1x2x3x4])=[−7−1−1−5]
🔗(b) 🔗How can we express this in terms of matrix multiplication? [3−2−2−42−1−1−1−10100−10−2][x1x2x3x4]=[−7−1−1−5] [x1x2x3x4]=[3−2−2−42−1−1−1−10100−10−2][−7−1−1−5] [x1x2x3x4][3−2−2−42−1−1−1−10100−10−2]=[−7−1−1−5] [x1x2x3x4]=[−7−1−1−5][3−2−2−42−1−1−1−10100−10−2]
🔗(c) 🔗 🔗How could a matrix equation of the form Ax→=b→ be solved for ?x→? Multiply: (RREFA)(Ax→)=(RREFA)b→ Add: (RREFA)+Ax→=(RREFA)+b→ Multiply: (A−1)(Ax→)=(A−1)b→ Add: (A−1)+Ax→=(A−1)+b→
🔗 Remark 4.3.3. 🔗The linear system described by the augmented matrix [A∣b→] has exactly the same solution set as the matrix equation .Ax→=b→. 🔗 🔗When A is invertible, then we have both [A∣b→]∼[I∣x→] and ,x→=A−1b→, which can be seen as Ax→=b→⇒A−1Ax→=A−1b→⇒x→=A−1b→
🔗 Activity 4.3.4. 🔗 🔗Consider the vector equation x1[12−2]+x2[−2−33]+x3[14−3]=[−35−1] 🔗with a unique solution. 🔗(a) 🔗Explain and demonstrate how this problem can be restated using matrix multiplication.🔗(b) 🔗Use the properties of matrix multiplication to find the unique solution.
🔗 Activity 4.3.5. 🔗Solving linear systems using matrix multiplication is most useful when we are working with one common coefficient matrix, and varying the right-hand side. That is, when we have Ax→=b→ for several different values of .b→. 🔗In the following, let A=[2−1−6213114] and consider the following questions about various equations of the form ?Ax→=b→? 🔗(a) 🔗 🔗Suppose that .b→=[111]. If asked to solve the equation ,Ax→=b→, which of the following approaches do you prefer? Calculate .RREF[A|b→]. Calculate A−1 and then compute x→=A−1b→ 🔗(b) 🔗 🔗Suppose that .b→1,b→2,b→3=[111],[213],[−135]. If asked to solve each of the equations ,Ax→=b→1,Ax→=b→2,Ax→=b→3, which of the following approaches do you prefer? Calculate ,RREF[A|b→1], ,RREF[A|b→2], and RREF[A|b→3] Calculate A−1 and then compute ,x→=A−1b→1, ,x→=A−1b→2, and x→=A−1b→3 🔗(c) 🔗 🔗Suppose that b→1,…,b→10 are 10 distinct vectors. If asked to solve each of the equations ,Ax→=b→1,…,Ax→=b→10, which of the following approaches do you prefer? Calculate ,RREF[A|b→1], ... .RREF[A|b→10]. Calculate A−1 and then compute ,x→=A−1b→1, ... .x→=A−1b→10.
🔗(a) 🔗 🔗Suppose that .b→=[111]. If asked to solve the equation ,Ax→=b→, which of the following approaches do you prefer? Calculate .RREF[A|b→]. Calculate A−1 and then compute x→=A−1b→
🔗(b) 🔗 🔗Suppose that .b→1,b→2,b→3=[111],[213],[−135]. If asked to solve each of the equations ,Ax→=b→1,Ax→=b→2,Ax→=b→3, which of the following approaches do you prefer? Calculate ,RREF[A|b→1], ,RREF[A|b→2], and RREF[A|b→3] Calculate A−1 and then compute ,x→=A−1b→1, ,x→=A−1b→2, and x→=A−1b→3
🔗(c) 🔗 🔗Suppose that b→1,…,b→10 are 10 distinct vectors. If asked to solve each of the equations ,Ax→=b→1,…,Ax→=b→10, which of the following approaches do you prefer? Calculate ,RREF[A|b→1], ... .RREF[A|b→10]. Calculate A−1 and then compute ,x→=A−1b→1, ... .x→=A−1b→10.
🔗 Exploration 4.3.6. Use row reduction to find the inverse of the following general matrix. Give conditions on which this inverse exists. [1bcdefghi]
🔗 Exploration 4.3.7. Assume that H is invertible, and that HG is the zero matrix. Prove that G must be the zero matrix. Would this still be true if H were not invertible?